SWIM has recently aquired a single stage vaccuum pump with a 3 gallon collection chamber and has found himself in a situation where he has an abundent amount of Love mixed with a large amount of water.
SO, here he is, half a gallon of water with half a G in there...
He's tried pumping out the water as opposed t oevaporating it over a period of a week with a dehum (which is what the general consensus has been) but he assumes this method will only decrease the potency due to the exposure of elements
The problem is that this vaccuum pump method was working for small batches until a practice run hat ran for 4hours yeilded oil from the motor suspended on top of the solution after too much moisture was collected in pump.
Any suggestions on evaporating excessive amounts of h20 out of solution?

-All love

try a rotovap

Make sure your cold trap is cold enough and your condenser is set properly.

Bonus: supply a argon or nitrogen gas atmosphere to combat oxidation/chemical deterioration

Maybe my initial head calculations are off, but wouldn't that half gallon be potent enough to be used as liquid?

1/2 galon =1892.7 mL
1g = 1000mg
1mg = 1000ug

So 1mg is 10 100ug doses, 10 x 1000mg = 10,000 100ug doses in that gram.

1892.7/10k ~ .19ml per dose

Someone correct me if I'm just bad at math

You're basically right but he said half a G. So 100ug would be in about half an mL of liquid which is totally fine, except it's not what people are used to. In other words, I'm guessing this liquid is not for the poster, but for other people that he intends to give or sell it to. People generally expect liquid L to be about 100ug per drop unless otherwise stated.