Harmala salts (both HCL and acetic anyway) are very water soluble. 1 gram will dissolve in less than 10 ml of water, faster if the water is hot.
macguyver wrote:If the alkaloids are in the brown sludge - then how will adding carb / filtering do anything? They'll still be with the brown, no? Or will repeated carb washes leech the brown from the sludge into the water?
It might force out more alkaloids from the solution. The higher the pH gets, the less soluble the freebase is. Adding ionic molecules to the solution will also decrease the freebase's solubility. It will not "unbrown" the already precipitated alkaloids.
macguyver wrote:Will the manske turn the freebase back into a HCL (by adding the vinegar)? Does this step pull the alkaloids out of the sludge and dissolve them in the water?
The Manske procedure will first dissolve the harmala freebase in acetic acid (it is then no longer a freebase), then precipitate it as a solid HCl salt through ion exchange with dissolved NaCl.
macguyver wrote:If this is the case (that the alkaloids are now in the solution) - can you filter the solution at this point to remove all the 'brown', then add the salt to the solution again to turn the HCL back into a freebase? (actually just realised I've possibly conflated 'adding salt' and 'base precipitation' (which I assume to be sodium carbonate) into one... are they one, or do these steps have different uses?
"Basing" and "salting out" are not the same procedure.
You can remove some of the brown by repeated filtering of the dissolved ionic form of the harmala alkaloids, or by repeated washing (shaking with clean alkaline water) of the freebase harmala alkaloids. You will likely not get a white powder ever, certainly not when starting out with 1 gram of crude harmalas. Even harmala HCl salts that are pure needles and look bright yellow will be off-white or tan when freebased.
macguyver wrote:How much freebase should I get from 1g HCL? (this is a separate extraction to the above (where I had 3g rue extract) - with this one, I had 1g 99.7% Harmine HCL) I think I've ended up with about .3g, which is terrible. It seems I have gifted the rest to various kitchen utensils due to the ridiculous amount of water I ended up using.
The amount of water does look a bit excessive. The HCl salt is usually a monohydrate, so it is the weight of 1 part harmala freebase + 1 part HCl + 1 part H20. -> 214.3 + 36.5 + 18.0 = 268.8. When you divide the two, you end up with a ratio of about 80%. So 1 gram HCl salt should theoretically yield 0.8 gram freebase. In practice you will get less due to mechanical losses (stuff sticking to the filter, the jar, the spoon etc.) and due to the fact that the freebase is still a bit soluble in alkaline water. Using less water will save more product, but will also save more impurities.
(After typing all of this, I see endlessness already answered. He uses a different calculation for the ratio, though. Maybe this can be cleared up.)